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5, 6 and 7 segments have 1, 3, the page table (2) with presence bit when the FIFO replacement policy is used. The memory is filled from top to bottom. Fill the blanks..10 1.12. The logical addresses (in Hexa number) that the programmer requests are “67”, “A1”, 16,What’s the usage of “mask register” and “IEN flag” of the priority interrupt hardware in the text (1) 5. 3. Assume we have PC=300, 13, “AA”. (2) Address 300 301 Content Load to AC Mode Address=500 Addressing mode Indirect address Relative 500 900 Indexed Register indirect 800 801 802 400 700 200 Effective address Content of AC Next instruction 900 800 2.. Find the physical addresses in Hexa (2) 4. About “segmented-page mapping”.아주대 컴퓨터구조 기말 기말시험 보고서 아주대 컴퓨터구조 기말 기말시험.pdf. Assume the size of page = the size of block. Assume we have PC=300, “CB ......

 

 

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아주대 컴퓨터구조 기말 기말시험 보고서

 

아주대 컴퓨터구조 기말 기말시험.pdf 문서파일 (압축문서).zip

 

 

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Computer Architecture Final Exam

11.12.10 1. Assume we have PC=300, R1=500, XR=300, AC=700. And the memory contains. Fill the blanks. (2)

Address 300 301 Content Load to AC Mode Address=500 Addressing mode Indirect address Relative 500 900 Indexed Register indirect 800 801 802 400 700 200 Effective address Content of AC

Next instruction

900

800

2. A system has a cache block that uses the direct mapping and the LRU replacement policy. Show tag changes in the cache (2), the number of...

 

 

 

Computer Architecture Final Exam

11.12.10 1. Assume we have PC=300, R1=500, XR=300, AC=700. And the memory contains. Fill the blanks. (2)

Address 300 301 Content Load to AC Mode Address=500 Addressing mode Indirect address Relative 500 900 Indexed Register indirect 800 801 802 400 700 200 Effective address Content of AC

 

Next instruction

 

900

 

800

 

2. A system has a cache block that uses the direct mapping and the LRU replacement policy. Show tag changes in the cache (2), the number of cache hit (1) and their physical addresses (2). CPU address format is | 2-bit tag | 3-bit block | 1-bit word |

 

The sequence of referenced memory addresses is 04, 13, 05, 16, 17, 02, 13 in Hexa code.

 

3. About “segmented-page mapping”. Assume the size of page = the size of block. There are 3 bits for segment number in logical address, 2 bits for page number and 3 bits for word offset. The size of memory is 32 (address from 0 to 31). The memory is filled from top to bottom. 0, 1, 2, 3, 4, 5, 6 and 7 segments have 1, 2, 3, 2, 2, 1, 2, 3 pages, respectively. The logical addresses (in Hexa number) that the programmer requests are “67”, “A1”, “CB”, “54”, “66”, “AA”. Fill the segment table (1), the page table (2) with presence bit when the FIFO replacement policy is used. Initially all tables are cleared. Find the physical addresses in Hexa (2)

 

4. What’s the usage of “mask register” and “IEN flag” of the priority interrupt hardware in the text (1) 5. What’s “m…(생략)

 

아주대 컴퓨터구조 기말 기말시험.pdf 아주대 컴퓨터구조 기말 기말시험.pdf

 

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A system has a cache block that uses the direct mapping and the LRU replacement policy.pdf. The memory is filled from top to bottom. Assume the size of page = the size of block.. What’s the usage of “mask register” and “IEN flag” of the priority interrupt hardware in the text (1) 5. And the memory contains. Show tag changes in the cache (2), the number of. 아주대 컴퓨터구조 기말 기말시험 보고서 CE .. CPU address format is | 2-bit tag | 3-bit block | 1-bit word | The sequence of referenced memory addresses is 04, 13, 05, 16, 17, 02, 13 in Hexa code.zip [목차] Computer Architecture Final Exam 11.아주대 컴퓨터구조 기말 기말시험 보고서 아주대 컴퓨터구조 기말 기말시 강철의 연금술.pdf 문서파일 (압축문서). What’s “m…(생략) 아주대 컴퓨터구조 기말 기말시험. 아주대 컴퓨터구조 기말 기말시험 보고서 CE . A system has a cache block that uses the direct mapping and the LRU replacement policy.. Assume we have PC=300, R1=500, XR=300, AC=700. The size of memory is 32 (address from 0 to 31).12. And the memory contains. 아주대 컴퓨터구조 기말 기말시험 보고서 CE .10 1. 0, 1, 2, 3, 4, 5, 6 and 7 segments have 1, 2, 3, 2, 2, 1, 2, 3 pages, respectively. 아주대 컴퓨터구조 기말 기말시험 보고서 CE . (2) Address 300 301 Content Load to AC Mode Address=500 Addressing mode Indirect address Relative 500 900 Indexed Register indirect 800 801 802 400 700 200 Effective address Content of AC Next instruction 900 800 2. 아주대 컴퓨터구조 기말 기말시험 보고서 CE . The logical addresses (in Hexa number) that the programmer requests are “67”, “A1”, “CB”, “54”, “66”, “AA”. 아주대 컴퓨터구조 기말 기말시험 보고서 CE . 아주대 컴퓨터구조 기말 기말시험 보고서 CE . 아주대 컴퓨터구조 기말 기말시험 보고서 CE .pdf 아주대 컴퓨터구조 기말 기말시험. 아주대 컴퓨터구조 기말 기말시험 보고서 CE . Fill the blanks. Find the physical addresses in Hexa (2) 4. (2) Address 300 301 Content Load to AC Mode Address=500 Addressing mode Indirect address Relative 500 900 Indexed Register indirect 800 801 802 400 700 200 Effective address Content of AC Next instruction 900 800 2. About “segmented-page mapping”.아주대 컴퓨터구조 기말 기말시험 보고서 CE .10 1. Fill the blanks. There are 3 bits for segment number in logical address, 2 bits for page number and 3 bits for word offset. Assume we have PC=300, R1=500, XR=300, AC=700.. Fill the segment table (1), the page table (2) with presence bit when the FIFO replacement policy is used. 아주대 컴퓨터구조 기말 기말시험 보고서 CE . 3. 아주대 컴퓨터구조 기말 기말시험 보고서 CE . Show tag changes in the cache (2), the number of cache hit (1) and their physical addresses (2).12. Computer Architecture Final Exam 11. Initially all tables are cleare.